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==== Example with single link association ==== | ==== Example with single link association ==== | ||
If you have | If you have a derived single link association called '''lastSubPart''', derived like | ||
self.subParts->last | self.subParts->last | ||
then you have a | then you have a method with this content | ||
let lp = self.lastSubPart in | let lp = self.lastSubPart in | ||
( | ( | ||
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You might expect newPart.Name to hold 'copy of <name of the lastsubpart>', but it doesn't. | You might expect newPart.Name to hold 'copy of <name of the lastsubpart>', but it doesn't. | ||
That's because '''lp''' is NOT holding '''the object''', it's holding | That's because '''lp''' is NOT holding '''the object''', it's holding a '''subscription to the derivation to the object'''. | ||
When the code does ''self.subParts.add(newPart)'', '''lp''' changes to point to the new object. | |||
I.e. every time you use '''lp''', the derived single link association is reevaluated. | |||
let lp = self.lastSubPart'''->first''' in | let lp = self.lastSubPart'''->first''' in | ||
( | ( |
Revision as of 16:41, 30 April 2020
let is used to temporarily assign a value to a variable in an EAL expression.
derived associations are used to create "shortcuts" in your model or to split complex navigations into parts.
Combining these two can lead to unexpected results.
Example with single link association
If you have a derived single link association called lastSubPart, derived like
self.subParts->last
then you have a method with this content
let lp = self.lastSubPart in ( self.subParts.add(newPart); newPart.Name = 'copy of ' + lp.Name )
You might expect newPart.Name to hold 'copy of <name of the lastsubpart>', but it doesn't.
That's because lp is NOT holding the object, it's holding a subscription to the derivation to the object.
When the code does self.subParts.add(newPart), lp changes to point to the new object.
I.e. every time you use lp, the derived single link association is reevaluated.
let lp = self.lastSubPart->first in ( self.subParts.add(newPart); newPart.Name = 'copy of ' + lp.Name )
The first operator here converts the object to a set and then takes the first, which is the same object, but breaks the subscription.